Statistics Chapter 12 Solutions

CHAPTER 12 TESTS FOR TWO OR MORE SAMPLES WITH CATEGORICAL DATA 1. When rilling for independence in a adventure table with 3 rows and 4 columns, thither argon ________ degrees of freedom. a) 5 b) 6 c) 7 d) 12 make b theatrical role MC bother flabby KEYWORDS chi-squ be examine of independence, degrees of freedom 2. If we use the pic method of epitome to thunder mugvas for the odd custodyts among 4 counterpoises, the degrees of freedom be equal to a) 3. b) 4. c) 5. d) 1. help a cause MC problem balmy KEYWORDS chi-squ be analyse for digression in ratios, degrees of freedom . If we wish to shape whether on that point is try out that the isotropy of successes is higher in con program 1 than in group 2, the captivate judge to use is a) the Z rill. b) the pic tryout. c) both of the in a higher place d) none of the above coiffe a token MC obstruction Easy KEYWORDS chi-squ are hear for divergency in proportions 4. If we wish to determine whether thither is e vidence that the proportion of successes is the identical in group 1 as in group 2, the appropriate tryout to use is a) the Z screen out. b) the pic shew. c) both of the above d) none of the above dish up face MC difficultness Easy KEYWORDS chi-square try on for going away in proportions 5. In examination a theory using the pic shew, the theoretical frequencies are based on the a) deceitful conjecture. b) option scheme. c) normal distribution. d) none of the above. help a persona MC obstacle Easy KEYWORDS chi-square examine for divergency in proportions, properties put back 12-1 A learning published in the Ameri rotter Journal of Public health was conducted to determine whether the use of piece of tail belts in labor vehicles depends on ethnic berth in San Diego County.A type of 792 children treated for injuries sustained from motor vehicle accidents was obtained, and each child was classified according to (1) ethnic status (Hispanic or non-Hispanic) and (2 ) seat belt usage ( faint or non worn) during the accident. The phone mo of children in each stratum is devoted in the table below. Hispanic Non-Hispanic Seat belts worn 31 148 Seat belts non worn 283 330 . Referring to defer 12-1, which running play would be utilize to properly try out the data in this experi ment? a) running for independence. b) ravel for dispute surrounded by proportions. c) ANOVA F block out for interaction in a 2 x 2 factorial design. d) running play for goodness of fit. fare a vitrine MC difficulty conduct KEYWORDS chi-square see of independence 7. Referring to board 12-1, the calculated analyse statistic is a) -0. 9991. b) -0. 1368. c) 48. 1849. d) 72. 8063. make c vitrine MC bother Easy KEYWORDS chi-square canvass of independence, test statistic 8.Referring to add-in 12-1, at 5% take aim of import, the deprecative harbor of the test statistic is a) 3. 8415. b) 5. 9914. c) 9. 4877. d) 13. 2767. ANSWER a slip MC bar Easy K EYWORDS chi-square test of independence, everyplace scathing protect 9. Referring to prorogue 12-1, at 5% aim of signifi burnce, there is sufficient evidence to abstain that the a) use of seat belts in motor vehicles is related to ethnic status in San Diego County. b) use of seat belts in motor vehicles depends on ethnic status in San Diego County. c) use of seat belts in motor vehicles is associated with ethnic status in San Diego County. ) every(prenominal) of the above ANSWER d typesetters case MC obstruction decrease KEYWORDS chi-square test of independence, finale, consequence submit 12-2 M each companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whether sucker awareness of female person TV viewers and the gender of the spokesperson are commutative. all(prenominal) in a sample of 300 female TV viewers was asked to discover a carrefour advertised by a celebrity spokesperson. The gender of the spok esperson and whether or not the viewer could identify the product was recorded. The numbers in each category are given below. Male Celebrity distaff Celebrity Identified product 41 61 Could not identify 109 89 10. Referring to dishearten 12-2, which test would be used to properly analyze the data in this experiment? a) test for independence. b) test for struggle between proportions. c) ANOVA F test for briny treatment effect. d) test for goodness of fit. ANSWER a case MC trouble Mode regularizeKEYWORDS chi-square test of independence 11. Referring to shelve 12-2, the calculated test statistic is a) -0. 1006. b) 0. 00. c) 5. 9418. d) 6. 1194. ANSWER c sign MC barrier Easy KEYWORDS chi-square test of independence, test statistic 12. Referring to prorogue 12-2, at 5% level of signifi substructurece, the unfavorable order of the test statistic is a) 3. 8415. b) 5. 9914. c) 9. 4877. d) 13. 2767. ANSWER a image MC difficulty Easy KEYWORDS chi-square test of independence, p articular economic observe 13. Referring to elude 12-2, the degrees of freedom of the test statistic are a) 1. b) 2. c) 4. ) 299. ANSWER a image MC obstacle Easy KEYWORDS chi-square test of independence, degrees of freedom 14. Referring to Table 12-2, at 5% level of import, the terminus is that a) brand awareness of female TV viewers and the gender of the spokesperson are self-employed person. b) brand awareness of female TV viewers and the gender of the spokesperson are not independent. c) brand awareness of female TV viewers and the gender of the spokesperson are related. d) both (b) and (c) ANSWER d suit MC obstacle Mode compute KEYWORDS chi-square test of independence, end, conclusion TABLE 12-3A computer used by a 24-hour banking service is supposed to stochasticly assign each transaction to one of 5 remembrance locations. A check at the end of a days proceedings gave the counts shown in the table to each of the 5 memory locations, along with the number of reporte d errors. Memory Location 1 2 3 4 5 Number of Transactions 82 100 74 92 102 Number of Reported Errors 11 12 6 9 10 The bank manager regarded to test whether the proportion of errors in transactions assigned to each of the 5 memory locations differ. 15. Referring to Table 12-3, which test would be used to properly analyze the data in this experiment? a) test for independence b) test for leaving between proportions c) ANOVA F test for main treatment effect d) test for goodness of fit ANSWER b cause MC bother find out KEYWORDS chi-square test for deviance in proportions 16. Referring to Table 12-3, the degrees of freedom of the test statistic is a) 4. b) 8. c) 10. d) 448. ANSWER a grapheme MC fuss EasyKEYWORDS chi-square test for rest in proportions, degrees of freedom 17. Referring to Table 12-3, the critical value of the test statistic at 1% level of significance is a) 7. 7794. b) 13. 2767. c) 20. 0902. d) 23. 2093. ANSWER b TYPE MC trouble Easy KEYWORDS chi-square test fo r end in proportions, critical value 18. Referring to Table 12-3, the calculated value of the test statistic is a) -0. 1777. b) -0. 0185. c) 1. 4999. d) 1. 5190. ANSWER c TYPE MC difficultness make KEYWORDS chi-square test for deviation in proportions, test statistic 19. Referring to Table 12-3, at 1% level of significance ) there is sufficient evidence to close that the proportions of errors in transactions assigned to each of the 5 memory locations are all diverse. b) there is meager evidence to conclude that the proportions of errors in transactions assigned to each of the 5 memory locations are all different. c) there is sufficient evidence to conclude that the proportion of errors in transactions assigned to each of the 5 memory locations are not all the same. d) there is insufficient evidence to conclude that the proportion of errors in transactions assigned to each of the 5 memory locations are not all the same.ANSWER d TYPE MC DIFFICULTY conquer KEYWORDS chi-square t est for loss in proportions, decision, conclusion 20. Moving companies are essential by the government to publish a Carrier Per conformityance Report each course of instruction. One of the descriptive statistics they must include is the annual percentage of shipments on which a $50 or greater adduce for loss or damage was filed. Suppose deuce companies, Econo-Move and On-the-Move, each decide to estimate this figure by sampling their records, and they report the data shown in the future(a) table. Econo-Move On-the-Move Total shipments sampled 900 750 Number of shipments with a claim pic $50 162 60 The owner of On-the-Move is hoping to use these data to show that the company is superior to Econo-Move with regard to the percentage of claims filed. Which test would be used to properly analyze the data in this experiment? a) test for independence b) test for goodness of fit ) ANOVA F test for main treatment effect d) test for the fight between proportions ANSWER d TYPE MC DIFFI CULTY buffer KEYWORDS Z test for difference in twain proportions 21. The Wall Street Journal deep ran an denomination indicating differences in the perception of inner bedevilment on the job between men and women. The article claimed that women perceived the problem to be frequently much(prenominal)(prenominal) prevalent than did men. One question asked to both men and women was Do you think versed torture is a major problem in the American study? Some 24% of the men, compared to 62% of the women, responded Yes. presumptuous W designates womens responses and M designates mens, what surmise should The Wall Street Journal test in order to show that its claim is true? a) H0 pW pM pic 0 versus H1 pW pM 0 b) H0 pW pM pic 0 versus H1 pW pM 0 c) H0 pW pM = 0 versus H1 pW pM pic 0 d) H0 (W (M pic 0 versus H1 (W (M 0 ANSWER b TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in 2 proportions, form of dead reckoning 22. The Wall Street Journal recently ran an article indicating differences in perception of intimate harassment on the job between men and women.The article claimed that women perceived the problem to be untold more(prenominal) prevalent than did men. One question asked to both men and women was Do you think sexual harassment is a major problem in the American workplace? Some 24% of the men, compared to 62% of the women, responded Yes. Suppose that cl women and cc men were interviewed. For a 0. 01 level of significance, what is the critical value for the rejection region? a) 7. 173 b) 7. 106 c) 6. 635 d) 2. 33 ANSWER d TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in 2 proportions, critical value 23.The Wall Street Journal recently ran an article indicating differences in perception of sexual harassment on the job between men and women. The article claimed that women perceived the problem to be much more prevalent than did men. One question asked to both men and women was Do you think sexual harassment is a major problem in the American workplace? Some 24% of the men, compared to 62% of the women, responded Yes. Suppose that cl women and 200 men were interviewed. What is the value of the test statistic? a) 7. 173 b) 7. 106 c) 6. 635 d) 2. 33 ANSWER a TYPE MC DIFFICULTY ModerateKEYWORDS Z test for difference in two proportions, test statistic 24. The Wall Street Journal recently ran an article indicating differences in perception of sexual harassment on the job between men and women. The article claimed that women perceived the problem to be much more prevalent than did men. One question asked to both men and women was Do you think sexual harassment is a major problem in the American workplace? Some 24% of the men, compared to 62% of the women, responded Yes. Suppose that 150 women and 200 men were interviewed. What conclusion should be reached? a) victimisation a 0. 1 level of significance, there is sufficient evidence to conclude that women perceive the problem of sexual harass ment on the job as being much more prevalent than do men. b) on that point is insufficient evidence to conclude with at least 99% confidence that women perceive the problem of sexual harassment on the job as being much more prevalent than do men. c) there is no evidence of a significant difference between the men and women in their perception. d) More information is call for to draw any conclusions from the data set. ANSWER a TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, decision, conclusion 5. A regent(postnominal) womens group has claimed that men and women differ in attitudes about sexual discrimination. A group of 50 men (group 1) and 40 women (group 2) were asked if they thought sexual discrimination is a problem in the United give tongue tos. Of those sampled, 11 of the men and 19 of the women did believe that sexual discrimination is a problem. Which of the following are the appropriate useless and substitute hypotheses to test the grou ps claim? a) H0 pW pM pic 0 versus H1 pW pM 0 b) H0 pW pM pic 0 versus H1 pW pM 0 c) H0 pW pM = 0 versus H1 pW pM pic 0 ) H0 (W (M pic 0 versus H1 (W (M 0 ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, form of conjecture 26. A powerful womens group has claimed that men and women differ in attitudes about sexual discrimination. A group of 50 men (group 1) and 40 women (group 2) were asked if they thought sexual discrimination is a problem in the United States. Of those sampled, 11 of the men and 19 of the women did believe that sexual discrimination is a problem. Find the value of the test statistic. a) Z = 2. 55 b) Z = 0. 85 c) Z = 1. 05 d) Z = 1. 20ANSWER a TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, test statistic 27. A powerful womens group has claimed that men and women differ in attitudes about sexual discrimination. A group of 50 men (group 1) and 40 women (group 2) were asked if they t hought sexual discrimination is a problem in the United States. Of those sampled, 11 of the men and 19 of the women did believe that sexual discrimination is a problem. If the p value turns out to be 0. 035 (which is NOT the real value in this data set), then a) at pic = 0. 05, we should fail to reject H0. ) at pic = 0. 04, we should reject H0. c) at pic = 0. 03, we should reject H0. d) None of the above would be correct statements. ANSWER b TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, decision, conclusion TABLE 12-4 A some eld ago, Pepsi invited consumers to take the Pepsi Challenge. Consumers were asked to decide which of two sodas, Coke or Pepsi, they preferred in a blind taste test. Pepsi was interest in determining what factors played a role in peoples taste preferences. One of the factors studied was the gender of the consumer.Below are the results of analyses comparing the taste preferences of men and women, with the proportions depicting preference for Pepsi. Males n = 109, pSM = 0. 422018Females n = 52, pSF = 0. 25 pSM pSF = 0. 172018Z = 2. 11825 28. Referring to Table 12-4, to determine if a difference exists in the taste preferences of men and women, give the correct alternative hypothesis that Pepsi would test. a) H1 pic b) H1 pic c) H1 pM pF pic 0 d) H1 pM pF = 0 ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, form of hypothesis 29.Referring to Table 12-4, suppose Pepsi wanted to test to determine if the males preferred Pepsi more than the females. Using the test statistic given, compute the appropriate p-value for the test. a) 0. 0171 b) 0. 0340 c) 0. 2119 d) 0. 4681 ANSWER a TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, p-value 30. Referring to Table 12-4, suppose Pepsi wanted to test to determine if the males preferred Pepsi less than the females. Using the test statistic given, compute the appropriate p-value for the test. a) 0. 0170 b ) 0. 0340 c) 0. 9660 d) 0. 9830 ANSWER d TYPE MC DIFFICULTY ModerateKEYWORDS Z test for difference in two proportions, p-value 31. Referring to Table 12-4, suppose that the two-tailed p-value was really 0. 0734. State the proper conclusion. a) At pic = 0. 05, there is sufficient evidence to destine the proportion of males preferring Pepsi differs from the proportion of females preferring Pepsi. b) At pic = 0. 10, there is sufficient evidence to indicate the proportion of males preferring Pepsi differs from the proportion of females preferring Pepsi. c) At pic = 0. 05, there is sufficient evidence to indicate the proportion of males preferring Pepsi equals the proportion of females preferring Pepsi. ) At pic = 0. 08, there is insufficient evidence to indicate the proportion of males preferring Pepsi differs from the proportion of females preferring Pepsi. ANSWER b TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, decision, conclusion TABLE 12-5 The follo wing Excel output contains the results of a test to determine if the proportions of live up to guests at two resorts are the same or different. Hypothesized Difference 0 Level of Significance 0. 5 aggroup 1 Number of Successes 163 Sample Size 227 base 2 Number of Successes 154 Sample Size 262 separate 1 counterbalance 0. 18061674 Group 2 Proportion 0. 58778626 Difference in Two Proportions 0. 130275414 norm Proportion 0. 648261759 Test Statistic 3. 00875353 Two-Tailed Test Lower Critical Value -1. 59961082 Upper Critical Value 1. 959961082 p-Value 0. 002623357 32. Referring to Table 12-5, allowing for 0. 75% probability of committing a Type I error, what are the decision and conclusion on testing whether there is any difference in the proportions of satisfied guests in the two resorts? a.Do not reject the nonentity hypothesis there is enough evidence to conclude that there is significant difference in the proportions of satisfied guests at the two resor ts. b. Do not reject the deceitful hypothesis there is not enough evidence to conclude that there is significant difference in the proportions of satisfied guests at the two resorts. c. Reject the unsubstantial hypothesis there is enough evidence to conclude that there is significant difference in the proportions of satisfied guests at the two resorts. d.Reject the null hypothesis there is not enough evidence to conclude that there is significant difference in the proportions of satisfied guests at the two resorts. ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, decision, conclusion 33. Referring to Table 12-5, if you want to test the claim that Resort 1 (Group 1) has a higher proportion of satisfied guests than Resort 2 (Group 2), the p-value of the test result be a) 0. 00262. b) 0. 00262/2. c) 2*(0. 00262). d) 1-(0. 00262/2). ANSWER bTYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, p-value 34. Referring to Table 12-5, if you want to test the claim that Resort 1 (Group 1) has a lower proportion of satisfied guests than Resort 2 (Group 2), you leave alone use a) a t test for the difference in two proportions. b) a Z test for the difference in two proportions. c) a pic test for the difference in two proportions. d) a pic test for independence. ANSWER b TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportionsTABLE 12-6 One criterion used to evaluate employees in the assembly section of a mammoth factory is the number of tarnishive pieces per 1,000 move produced. The tone of voice control department wants to find out whether there is a affinity between grades of experience and desolate rate. Since the job is repetitious, after the initial training period, any improvement due to a learning effect might be offset by a loss of motivation. A defect rate is calculated for each worker in a gradely evaluation. The results for 100 workers are given in the table below. age Since Training Period 1 Year 1 4 Years 5 9 Years High 6 9 9 Defect Rate Average 9 19 23 Low 7 8 10 5. Referring to Table 12-6, which test would be used to properly analyze the data in this experiment to determine whether there is a relationship between defect rate and years of experience? a) pictest for independence in a two-way misfortune table b) pictest for equal proportions in a one-way table c) ANOVA F test for main treatment effect d) Z test for the difference in two proportions ANSWER a TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence 36. Referring to Table 12-6, find the rejection region necessary for testing at the 0. 5 level of significance whether there is a relationship between defect rate and years of experience. a) Reject H0 if pic 16. 919. b) Reject H0 if pic 15. 507. c) Reject H0 if pic 11. 143. d) Reject H0 if pic 9. 488. ANSWER d TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, critical value 37. Referring to T able 12-6, what is the judge number of employees with less than 1 year of training duration and a high defect rate? a) 4. 17 b) 4. 60 c) 5. 28 d) 9. 17 ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, misfortune table, properties 8. Referring to Table 12-6, what is the expected number of employees with 1 to 4 years of training succession and a high defect rate? a) 12. 00 b) 8. 64 c) 6. 67 d) 6. 00 ANSWER b TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, misadventure table, properties 39. Referring to Table 12-6, of the mobile phone for 1 to 4 years of training time and a high defect rate, what is the contribution to the boilersuit pic statistic for the independence test? a) 0. 36 b) 0. 1296 c) 0. 015 d) 0. 0144 ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, contingency table, properties 0. Referring to Table 12-6, a test was conducted to determine if a relationship exists between defect rate an d years of experience. Which of the following p-values would indicate that defect rate and years of experience are dependent? Assume you are testing at pic = 0. 05. a) 0. 045 b) 0. 055 c) 0. 074 d) 0. 080 ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, p-value, decision TABLE 12-7 A corporation randomly selects 150 salespeople and finds that 66% who ca-ca never taken a self-reformation course would like to take such a course.The substantial did a similar study 10 years ago in which 60% of a random sample of 160 salespeople wanted to take a self-improvement course. The groups are assumed to be independent random samples. Let p1 and p2 represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study, respectively. 41. Referring to Table 12-7, if the firm wanted to test whether this proportion has changed from the old study, which represents the relevant hypotheses? a) H0 p1 p2 = 0 versus H 1 p1 p2 pic 0 b) H0 p1 p2 pic 0 versus H1 p1 p2 = 0 ) H0 p1 p2 pic 0 versus H1 p1 p2 0 d) H0 p1 p2 pic 0 versus H1 p1 p2 0 ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions 42. Referring to Table 12-7, if the firm wanted to test whether a greater proportion of workers would currently like to attend a self-improvement course than in the past, which represents the relevant hypotheses? a) H0 p1 p2 = 0 versus H1 p1 p2 pic 0 b) H0 p1 p2 pic 0 versus H1 p1 p2 = 0 c) H0 p1 p2 pic 0 versus H1 p1 p2 0 ) H0 p1 p2 pic 0 versus H1 p1 p2 0 ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, form of hypothesis 43. Referring to Table 12-7, what is the unbiased point estimate for the difference between the two nation proportions? a) 0. 06 b) 0. 10 c) 0. 15 d) 0. 22 ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS point estimate 44. Referring to Table 12-7, what is/are the cri tical value(s) when makeing a Z test on whether population proportions are different if pic = 0. 05? a) pic 1. 645 b) pic 1. 96 c) -1. 96 d) pic 2. 8 ANSWER b TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, critical value 45. Referring to Table 12-7, what is/are the critical value(s) when testing whether population proportions are different if pic = 0. 10? a) pic 1. 645 b) pic 1. 96 c) -1. 96 d) pic 2. 08 ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, critical value 46. Referring to Table 12-7, what is/are the critical value(s) when testing whether the current population proportion is higher than before if pic = 0. 05? a) pic1. 645 b) + 1. 45 c) pic1. 96 d) + 1. 96 ANSWER b TYPE MC DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, critical value 47. Referring to Table 12-7, what is the estimated standard error of the difference between the two sample proportions? a) 0. 629 b) 0. 500 c) 0. 055 d) 0 ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, standard error 48. Referring to Table 12-7, what is the value of the test statistic to use in evaluating the alternative hypothesis that there is a difference in the two population proportions? ) 4. 335 b) 1. 96 c) 1. 093 d) 0 ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, chi-square test for difference in proportions, test statistic 49. Referring to Table 12-7, the company tests at the 0. 05 level to determine whether the population proportion has changed from the previous study. Which of the following is most correct? a) Reject the null hypothesis and conclude that the proportion of employees who are arouse in a self-improvement course has changed over the intervening 10 years. ) Do not reject the null hypothesis and conclude that the proportion of employees who are interested in a self-improvement course has not changed over the intervening 10 years. c) Reject the null hypothesis and conclude that the proportion of employees who are interested in a self-improvement course has increased over the intervening 10 years. d) Do not reject the null hypothesis and conclude that the proportion of employees who are interested in a self-improvement course has increased over the intervening 10 years. ANSWER b TYPE MC DIFFICULTY ModerateKEYWORDS Z test for difference in two proportions, chi-square test for difference in proportions, decision, conclusion 50. accepted or nonsensical In testing the difference between two proportions, we may use either a one-tailed chi-square test or two-tailed Z test. ANSWER real TYPE TF DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, chi-square test for difference in proportions 51. align or unreasonable The squared difference between the observed and theoretical frequencies should be large if there is no significant difference between the proportions.ANSWER ridiculous TYPE TF DIFFICU LTY Easy KEYWORDS chi-square test for difference in proportions, properties 52. straightforward or bastard A test for the difference between two proportions can be performed using the chi-square distribution. ANSWER uncoiled TYPE TF DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions 53. current or False A test for whether one proportion is higher than the other can be performed using the chi-square distribution. ANSWER False TYPE TF DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions 54.True or False When using the pic tests for independence, one should be aware that expected frequencies that are too runty will lead to too big a Type I error. ANSWER True TYPE TF DIFFICULTY Difficult KEYWORDS chi-square test of independence, properties, assumption 55. True or False If we use the chi-square method of analysis to test for the difference between proportions, we must assume that there are at least 5 observed frequencies in each carrell of the contingency table. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test of independence, properties, assumption 6. If we wish to determine whether there is evidence that the proportion of successes is higher in Group 1 than in Group 2, and the test statistic for Z = +2. 07, the p-value is equal to ______. ANSWER 0. 0192 TYPE FI DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, p-value TABLE 12-8 The dean of a college is interested in the proportion of graduates from his college who have a job offer on graduation day. He is particularly interested in seeing if there is a difference in this proportion for accounting and economics majors.In a random sample of 100 of each type of major at graduation, he found that 65 accounting majors and 52 economics majors had job offers. If the accounting majors are designated as Group 1 and the economics majors are designated as Group 2, perform the appropriate hypothesis test using a level of significance of 0. 05. 57. Referring to Table 12-8, the hypotheses the dean should use are a) H0 p1 p2 = 0 versus H1 p1 p2 pic 0. b) H0 p1 p2 pic 0 versus H1 p1 p2 = 0. c) H0 p1 p2 pic 0 versus H1 p1 p2 0. d) H0 p1 p2 pic 0 versus H1 p1 p2 0.ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, form of hypothesis 58. Referring to Table 12-8, the null hypothesis will be rejected if the test statistic is ________. ANSWER Z 1. 96 or -1. 96 or pic 3. 841 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, critical value 59. Referring to Table 12-8, the value of the test statistic is ________. ANSWER Z = 1. 866 or pic = 3. 4806 TYPE FI DIFFICULTY ModerateKEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, test statistic 60. Referring to Table 12-8, the p-value of the test is ________. ANSWER 0. 0621 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, p-value 61. True or False Referring to Table 12-8, the null hypothesis should be rejected. ANSWER False TYPE TF DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, decision 62.True or False Referring to Table 12-8, the same decision would be made with this test if the level of significance had been 0. 01 sooner than 0. 05. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, decision 63. True or False Referring to Table 12-8, the same decision would be made with this test if the level of significance had been 0. 10 rather than 0. 05. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Z test for difference in two proportions, decision TABLE 12-9A quality control engineer is in charge of the manufacture of computer disks. Two different processes can be used to manufacture the disks. He suspects that the Kohler method produces a greater proportion of defects than the Russell method. He samples 150 of the Kohler and 200 of the Russell disks and finds that 27 and 18 of them, respectively, are defective. If Kohler is designated as Group 1 and Russell is designated as Group 2, perform the appropriate test at a level of significance of 0. 01. 64. Referring to Table 12-9, the hypotheses that should be tested are a) H0 p1 p2 = 0 versus H1 p1 p2 pic 0. ) H0 p1 p2 pic 0 versus H1 p1 p2 = 0. c) H0 p1 p2 pic 0 versus H1 p1 p2 0. d) H0 p1 p2 pic 0 versus H1 p1 p2 0. ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, form of hypothesis 65. Referring to Table 12-9, the null hypothesis will be rejected if the test statistic is ________. ANSWER Z 2. 33 TYPE FI DIFFICULTY Easy KEYWORDS Z test for difference in two proportions, cri tical value 66. Referring to Table 12-9, the value of the test statistic is ________. ANSWER 2. 49 TYPE FI DIFFICULTY ModerateKEYWORDS Z test for difference in two proportions, test statistic 67. Referring to Table 12-9, the p-value of the test is ________. ANSWER 0. 0064 TYPE FI DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, p-value 68. True or False Referring to Table 12-9, the null hypothesis should be rejected. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS Z test for difference in two proportions, decision 69. True or False Referring to Table 12-9, the same decision would be made with this test if the level of significance had been 0. 05 rather than 0. 01. ANSWER True TYPE TF DIFFICULTY ModerateKEYWORDS Z test for difference in two proportions, decision 70. True or False Referring to Table 12-9, the same decision would be made if this had been a two-tailed test at a level of significance of 0. 01. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS Z tes t for difference in two proportions, decision TABLE 12-10 The director of transportation of a large company is interested in the usage of her van pool. She considers her routes to be divided into local and non-local. She is particularly interested in learning if there is a difference in the proportion of males and females who use the local routes.She takes a sample of a days riders and finds the following Male Female Total Local 27 44 71 Non-Local 33 25 58 Total 60 69 129 She will use this information to perform a chi-square hypothesis test using a level of significance of 0. 05. 71. Referring to Table 12-10, the test will refer _________ degree(s) of freedom. ANSWER 1TYPE FI DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, degrees of freedom 72. Referring to Table 12-10, the overall or ordinary proportion of local riders is __________. ANSWER 0. 550 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, properties 73. Referring to Table 12-10, the expected cell frequency in the Male/Local cell is __________. ANSWER 33. 02 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, contingency table, properties 74. Referring to Table 12-10, the expected cell frequency in the Female/Non-Local cell is __________.ANSWER 31. 02 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, contingency table, properties 75. Referring to Table 12-10, the critical value of the test is _________. ANSWER 3. 841 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, critical value 76. Referring to Table 12-10, the value of the test statistic is _________. ANSWER 4. 568 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, test statistic 77. True or False Referring to Table 12-10, the null hypothesis will be rejected.ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, decisio n 78. True or False Referring to Table 12-10, the decision made suggests that there is a difference between the proportion of males and females who ride local versus non-local routes. ANSWER True TYPE TF DIFFICULTY Median KEYWORDS chi-square test for difference in proportions, conclusion TABLE 12-11 Four surgical procedures are currently used to build pacemakers. If the patient does not need to return for follow-up surgery, the operation is called a piss operation.A heart vegetable marrow wants to compare the proportion of clear operations for the 4 procedures, and collects the following numbers of patients from their own records Procedure A B C D Total shit 27 41 21 7 96 Return 11 15 9 11 46 Total 38 56 30 18 142 They will use this information to test for a difference among the proportion of clear operations using a chi-square test with a level of significance of 0. 05. 79. Referring to Table 12-11, the test will involve _________ degrees of freedom. ANSWER 3 TYPE FI DIF FICULTY Easy KEYWORDS chi-square test for difference in proportions, degrees of freedom 80. Referring to Table 12-11, the overall or ordinary proportion of clear operations is __________. ANSWER 0. 676 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, properties 81.Referring to Table 12-11, the expected cell frequency for the Procedure A/Clear cell is __________. ANSWER 25. 69 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, contingency table, properties 82. Referring to Table 12-11, the expected cell frequency for the Procedure D/Return cell is __________. ANSWER 5. 83 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, contingency table, properties 83. Referring to Table 12-11, the critical value of the test is ________. ANSWER 7. 815 TYPE FI DIFFICULTY EasyKEYWORDS chi-square test for difference in proportions, critical value 84. Referring to Table 12-11, the value of the test statis tic is _________. ANSWER 7. 867 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, test statistic 85. True or False Referring to Table 12-11, the null hypothesis will be rejected. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, decision 86. True or False Referring to Table 12-11, the decision made suggests that the 4 procedures all have different proportions of clear operations.ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, conclusion 87. True or False Referring to Table 12-11, the decision made suggests that the 4 procedures do not all have the same proportion of clear operations. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, conclusion TABLE 12-12 The director of memory accesss at a state college is interested in seeing if admissions status (admitted, waiting list, denied admission) at his college is i ndependent of the type of residential district in which an applicant resides.He takes a sample of recent admissions decisions and forms the following table Admitted Wait List Denied Total Urban 45 21 17 83 Rural 33 13 24 70 Suburban 34 12 39 85 Total 112 46 80 238 He will use this table to do a chi-square test of independence with a level of significance of 0. 01. 88. Referring to Table 12-12, the test will involve _________ degrees of freedom. ANSWER 4 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test of independence, degrees of freedom 89. Referring to Table 12-12, the critical value of the test is _________. ANSWER 13. 277 TYPE FI DIFFICULTY Easy KEYWORDS chi-square test of independence, critical value 90. Referring to Table 12-12, the expected cell frequency for the Admitted/Urban cell is _________. ANSWER 39. 06TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test of independence, contingency table, properties 91. Referring to Table 12-12, the value of the test statistic is _________. ANSWER 12. 624 TYPE FI DIFFICULTY Moderate KEYWORDS chi-square test of independence, test statistic 92. True or False Referring to Table 12-12, the null hypothesis will be rejected. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test of independence, decision 93. True or False Referring to Table 12-12, the p-value of this test is greater than 0. 01. ANSWER TrueTYPE TF DIFFICULTY Moderate KEYWORDS chi-square test of independence, p-value 94. True or False Referring to Table 12-12, the decision made suggests that admissions status at the college is independent of the type of community in which an applicant resides. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, conclusion 95. True or False Referring to Table 12-12, the same decision would be made with this test if the level of significance had been 0. 005. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, decision 6. True or False Referring to Table 12-12, the same decision would be made with this test if the level of significance had been 0. 05. ANSWER False TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, decision 97. True or False Referring to Table 12-12, the null hypothesis claims that there is no association between admission status at the college and the type of community in which an applicant resides. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, form of hypothesis, conclusion 98.True or False Referring to Table 12-12, the alternative hypothesis claims that there is some connectedness between admission status at the college and the type of community in which an applicant resides. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, form of hypothesis, conclusion 99. True or False The chi-square test of independence requires that the number of expected frequency in each cell to be at least 5. ANSWER False TYPE TF DIFFICULTY Easy KEYWORDS chi-squ are test of independence, assumption 100.True or False The chi-square test of independence requires that the number of expected frequency in each cell to be at least 1. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, assumption TABLE 12-13 Parents complain that children read too few tale books and watch too much television nowadays. A survey of 1,000 children reveals the following information on number time exhausted ceremonial TV and average time pass reading figment books Average time dog-tired reading score books Average time pent watch TV Less than 1 hour Between 1 and 2 hours More than 2 hours Less than 2 hours 90 85 130 More than 2 hours 655 32 8 101. Referring to Table 12-13, how legion(predicate) children in the survey spent less than 2 hours reflexion TV and more than 2 hours reading history books, on average? a) 8 b) 130 c) 175 d) 687 ANSWER bTYPE MC DIFFICULTY Easy KEYWORDS contingency table, properties 102. Referring to Tab le 12-13, how some children in the survey spent less than 2 hours ceremonial occasion TV and no more than 2 hours reading story books, on average? a) 8 b) 130 c) 175 d) 687 ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS contingency table, properties 103. Referring to Table 12-13, if the null hypothesis of no connection between time spent watching TV and time spent reading story books is true, how many children watching less than 2 hours of TV and reading no more than 2 hours of story books, on average, can we expect? ) 35. 69 b) 227. 23 c) 262. 91 d) 969. 75 ANSWER c TYPE MC DIFFICULTY Difficult KEYWORDS chi-square test of independence, contingency table, properties 104. Referring to Table 12-13, if the null hypothesis of no connection between time spent watching TV and time spent reading story books is true, how many children watching less than 2 hours of TV and reading more than 2 hours of story books, on average, can we expect? a) 42. 09 b) 155. 25 c) 262. 92 d) 987. 75 ANSWER a TYP E MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, contingency table, properties 105.Referring to Table 12-13, to test whether there is any relationship between average time spent watching TV and average time spent reading story books, the value of the heedful test statistic is a) -12. 59. b) 1. 61. c) 481. 49. d) 1,368. 06. ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, test statistic 106. Referring to Table 12-13, suppose we want to constrain the probability of committing a Type I error to 5% when testing whether there is any relationship between average time spent watching TV and average time spent reading story books.The critical value will be a) 5. 991. b) 7. 378. c) 12. 592. d) 14. 449. ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, critical value 107. Referring to Table 12-13, we want to test whether there is any relationship between average time spent watching TV and average time spent reading story books. Suppose the value of the test statistic was 164 (which is not the correct answer) and the critical value was 19. 00 (which is not the correct answer), then we could conclude that a) there is a connection between time spent reading story books and time spent watching TV. ) there is no connection between time spent reading story books and time spent watching TV. c) more time spent reading story books leads to less time spent watching TV. d) more time spent watching TV leads to less time spent reading story books. ANSWER a TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, decision, conclusion TABLE 12-14 Recent studies have found that American children are more obese than in the past. The amount of time children spend watching television has received much of the blame.A survey of 100 ten-year-olds revealed the following with regards to weights and average number of hours a day spent watching television. We are interested in testing whether the average number of hours spent watching TV and weights are independent at 1% level of significance. Weights TV Hours Total 0-3 3-6 6+ More than 10 lbs. verweight 1 9 20 30 Within 10 lbs. of normal weight 20 15 15 50 More than 10 lbs. underweight 10 5 5 20 Total 31 29 40 100 108.Referring to Table 12-14, if there is no connection between weights and average number of hours spent watching TV, we should expect how many children to be spending 3-6 hours, on average, watching TV and are more than 10 lbs. underweight? a) 5 b) 5. 8 c) 6. 2 d) 8 ANSWER b TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, contingency table, properties 109. Referring to Table 12-14, if there is no connection between weights and average number of hours spent watching TV, we should expect how many children to be spending no more than 6 hours, on average, watching TV and are more than 10 lbs. nderweight? a) 5. 8 b) 6. 2 c) 8 d) 12 ANSWER d TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of indepen dence, contingency table, properties 110. Referring to Table 12-14, how many children in the survey spend more than 6 hours watching TV and are more than 10 lbs. overweight? a) 1 b) 9 c) 20 d) 40 ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, contingency table, properties 111. Referring to Table 12-14, how many children in the survey spend no more than 6 hours watching TV and are more than 10 lbs. underweight? a) 5 ) 10 c) 15 d) 20 ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, contingency table, properties 112. Referring to Table 12-14, the value of the test statistic is a) 8. 532. b) 15. 483. c) 18. 889. d) 69. 744. ANSWER c TYPE MC DIFFICULTY moderate KEYWORDS chi-square test of independence, test statistic 113. Referring to Table 12-14, the critical value of the test will be a) 6. 635. b) 13. 277. c) 14. 860. d) 21. 666. ANSWER b TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, critical value 114.Referring to Table 12-14, suppose the value of the test statistic was 30. 00 (which is not the correct value) and the critical value at 1% level of significance was 10. 00 (which is not the correct value), which of the following conclusions would be correct? a) We will accept the null and conclude that the average number of hours spent watching TV and weights are independent. b) We will reject the null and conclude that the average number of hours spent watching TV and weights are independent. c) We will accept the null and conclude that the average number of hours spent watching TV and weights are not independent. ) We will reject the null and conclude that the average number of hours spent watching TV and weights are not independent. ANSWER d TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test of independence, decision, conclusion 115. Referring to Table 12-14, which of the following statements is correct? a) We can accept the null for any level of significance greater than 0. 005 b) We ca n reject the null for any level of significance greater than 0. 005. c) We can accept the null for any level of significance smaller than 0. 005 d) We can reject the null for any level of significance smaller than 0. 05. ANSWER b TYPE MC DIFFICULTY Difficult KEYWORDS chi-square test of independence, decision 116. Referring to Table 12-14, the degrees of freedom of the test statistic are a) 1. b) 2. c) 4. d) 9. ANSWER c TYPE MC DIFFICULTY Easy KEYWORDS chi-square test of independence, degrees of freedom 117. True or False Referring to Table 12-14, the test is always a one-tailed test. ANSWER True TYPE TF DIFFICULTY Easy KEYWORDS chi-square test of independence, properties Table 12-15 According to an article in Marketing News, fewer checks are being written at grocery store checkout stands than in the past.To determine whether there is a difference in the proportion of shoppers who stipendiary by check over triad consecutive years at a 0. 05 level of significance, the results of a s urvey of 500 shoppers during three consecutive years are obtained and presented below. Year Check Written Year 1 Year 2 Year 3 Yes 225 175 125 No 275 325 375 118.Referring to Table 12-15, what is the expected number of shoppers who compensable by check in year 1 if there was no difference in the proportion of shoppers who paid by check over the three years? ANSWER 175 TYPE PR DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, properties 119. Referring to Table 12-15, what is the expected number of shoppers who did not pay by check in year 3 if there was no difference in the proportion of shoppers who paid by check over the three years? ANSWER 325 TYPE PR DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, properties 20. Referring to Table 12-15, what is the form of the null hypothesis? a) pic b) pic c) pic d) pic ANSWER a TYPE MC DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, forms of hypothesis 121. Referring t o Table 12-15, what is the form of the alternative hypothesis? a) pic b) pic c) pic d) pic not all pic are the same ANSWER d TYPE MC DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, forms of hypothesis 122. True or False Referring to Table 12-15, the assumptions needed to perform the test are satisfied. ANSWERTrue TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, assumption 123. Referring to Table 12-15, what are the degrees of freedom of the test statistic? ANSWER 2 TYPE PR DIFFICULTY Easy KEYWORDS chi-square test for difference in proportions, degrees of freedom 124. Referring to Table 12-15, what is the value of the test statistic? ANSWER 43. 96 TYPE PR DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, test statistic 125. Referring to Table 12-15, what is the critical value? ANSWER 5. 99 TYPE PR DIFFICULTY EasyKEYWORDS chi-square test for difference in proportions, critical value 126. Referring to Table 12-15, what is the p-value of the test statistic? ANSWER 2. 9E-10 or smaller than 0. 005 TYPE PR DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, p-value 127. True or False Referring to Table 12-15, the null hypothesis cannot be rejected. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, decision 128. Referring to Table 12-15, what is the correct conclusion? a) There is enough evidence that the proportions are all different in the 3 years. ) There is not enough evidence that the proportions are all different in the 3 years. c) There is enough evidence that at least two of the proportions are not equal. d) There is not enough evidence that at least two of the proportions are not equal. ANSWER c TYPE MC DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, conclusion 129. Referring to Table 12-15, what is the value of the critical tell for the Marascuilo procedure to test for the dif ference in proportions between year 1 and year 2 using a 0. 05 level of significance? ANSWER 0. 0754 TYPE PR DIFFICULTY DifficultKEYWORDS chi-square test for difference in proportions, Marascuilo procedure, critical value 130. Referring to Table 12-15, what is the value of the critical range for the Marascuilo procedure to test for the difference in proportions between year 1 and year 3 using a 0. 05 level of significance? ANSWER 0. 0722 TYPE PR DIFFICULTY Difficult KEYWORDS chi-square test for difference in proportions, Marascuilo procedure, critical range 131. Referring to Table 12-15, what is the value of the critical range for the Marascuilo procedure to test for the difference in proportions between year 2 and year 3 using a 0. 5 level of significance? ANSWER 0. 0705 TYPE PR DIFFICULTY Difficult KEYWORDS chi-square test for difference in proportions, Marascuilo procedure, critical value 132. True or False Referring to Table 12-15, there is sufficient evidence to conclude that t he proportions between year 1 and year 2 are different at a 0. 05 level of significance. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Marascuilo procedure, decision, conclusion 133.True or False Referring to Table 12-15, there is not sufficient evidence to conclude that the proportions between year 1 and year 3 are different at a 0. 05 level of significance. ANSWER False TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Marascuilo procedure, decision, conclusion 134. True or False Referring to Table 12-15, there is sufficient evidence to conclude that the proportions between year 2 and year 3 are different at a 0. 05 level of significance. ANSWER True TYPE TF DIFFICULTY Moderate KEYWORDS chi-square test for difference in proportions, Marascuilo procedure, decision conclusion